X^2+9x-148=0

Solution for X^2+9x-148=0 equation:

X^2+9X-148=0

a = 1; b = 9; c = -148;
Δ = b2-4ac
Δ = 92-4·1·(-148)
Δ = 673
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{673}}{2*1}=\frac{-9-\sqrt{673}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{673}}{2*1}=\frac{-9+\sqrt{673}}{2}
$